单项选择题

A.let users =[’zhangsan’,’lisi’,’wangwu’];for(let user of users){console.log(user);}
B.let users =[’zhangsan’,’lisi’,’wangwu’];for(let index in users){console.log(users[index]);}
C.let users =[’zhangsan’,’lisi’,’wangwu’];for(var user :users){console.log(user);}
D.let users =[’zhangsan’,’lisi’,’wangwu’];users.forEach(user =〉{console.log(user);})
E.let users =[’zhangsan’,lisi,wangwu’];for (let i =0;i 〈users.length;i++){console.log(users[i]);}
F.Let users =[zhangsan lisi ;wangwu’];users.forEach(function(val,index,user)(console.log(this,val,index,user);})